joeb33050
posted this
25 March 2016
John Alexander wrote: This discussion has gotten a lot more interesting than I expected. When it went from “is a spirit level better for controlling cant than the horizontal crosshair” to the the question of how important, or not, a few degrees of cant is and is that importance, or lack of importance, only at long range. I will admit that my head was spinning at times until I thought -- wait this is a geometry problem and I had that as a sophomore in high school. This isn't like trying to figure out what really happens to a cast bullet in the throat when the gun goes off. We don't have to rely on guesses, opinions, what is written somewhere by an authority (who may be wrong) or “what everybody is doing.” I think I finally have the geometry problem straightened out in my head and you can explain to me why not if I am wrong.
Assume we have a long range rifle with the long axis of the scope 2 inches above the axis of the bore and the axis of the scope (sight line) and the axis of the bore converging at 200 yards. (for what distance that convergence would zero the rifle would depend on velocity and BC of the bullet but is irrelevant for now ”€œ forget what the bullet is doing until later.)
Now assume that the rifle is canted 2 degrees from where it was uncanted the shot before. Joe's experiments showed that shooters are amazingly good at eliminating cant, so 2 degrees is a lot. By geometry (2” x sin 2 degrees) this puts axis of the bore 0.07” horizontally from where it was for the last shot in relation to the scope axis (no matter the center of rotation.) The vertical deflection (2 ”€œ 2 x cos 2 degrees) = 0.001” so we can ignore the vertical change. Both of these deflections are at the rifle and bench.
I GET THE SAME NUMBERS, .0698 AND .00122.
This will mean that although the sight line and axis of the bore will still converge at 200 yards, at 400 yards the bore axis will be located .07” to the opposite side that it was deflected towards back at the rifle. At 1,000 yards the axis of the bore will be 0.28 inches from where it was for the uncanted shot before.
YES, BECAUSE THE X HAIR CENTER IS ROTATING ABOUT THE ORIGINAL CENTER OF ROTATION, THE CENTER 2” FROM THE X HAIRS.
Where is the bullet? In some previously posts it was mentioned, or assumed, that the “trajectory was canted” when the rifle was canted. This can't be.
AGREE
Except for minor influences (latitude, twist, and direction rifle was pointed) and the usual major influence of wind, the trajectory will go relentlessly toward the center of mass of the earth (gravity) no matter how you cant the rifle.
If the analysis above is right then the error caused by inconsistent cant is equally important at all ranges ”€œ not much at all at any.
For instance the error at 1,000 yards caused by a 2 degree change in cant is about a quarter of an inch (0.7” for a yough 5 degree cant). Needless to say at a distance where the wind deflection may be varying in feet from one shot to the next this isn't the shooters biggest problem. If there are errors in my thinking or calculations please let me know.
ONE OF US IS WRONG HERE. I WROTE:
More precisely, cant is the rotation of the rifle about the axis going through the sights and the center of the target. The shooter will keep the sights aligned with the center of the target, and canting will rotate the rifle about the line going through the sights and to the target. As the rifle is rotated the impact point of the bullet moves in a circle of radius = drop of the bullet and center at the zero cant impact point - drop. Let's say that the drop is 6” over some range, and you have zeroed the rifle with no cant. Canting the rifle moves the bullet through a circle of 6” radius, and the center of the circle is 6” below the beginning, zero cant impact point.
Let R = radius and C = the cant angle in degrees, then horizontal deflection of the impact point = R Sin C and vertical deflection = -R-(R Cos C.)
The movement of the impact point is a function of the bullet drop and the angle of cant.
For any cant angle up to 10 degrees or so, the amount of vertical shift is a small fraction of the horizontal shift, and can be ignored for most applications.
Drop is a function of muzzle velocity and the Ballistic Coefficient (BC) of the bullet, and is easily estimated on a personal computer using one of the ballistics programs that are readily available.
A plain base cast bullet has a typical BC of .4, and is fired at around 1400 feet per second (f/s.) That bullet will drop 9.5” in 100 yards and 1449” in 1000 yards.
Canting the rifle to the right, for example, moves the impact point to the right and down thus:
Cant (degrees) 100 yd 100 yd 1000 yd 1000 yd
right” down” right” down”
1 .166 .001 25.3 .221
2 .332 .006 50.6 .883
3 .497 .013 75.8 1.986
4 .663 .023 101.1 3.530
IS IT ME?
John